Re: [OVC-discuss] What if N of M contest is 96 of 600?

From: Alan Dechert <dechert_at_gmail_dot_com>
Date: Tue Dec 02 2008 - 22:15:48 CST

> My understanding from your description of the election is
> that voters are not assigning candidates to 96 specific,
> individual offices. Thus, you wouldn't need to keep track
> of each individual slot, would you? Voters would be
> ranking each candidate overall compared to all other
> candidates, not ranking each candidate for each slot. The
> filling of the available slots would be done by an
> algorithm running on the central tabulator after all votes
> have been tabulated. At most, there would be 96
> candidate IDs and 96 integer rankings on a single ballot.
> Is that too much for the 2-d barcode?
>
Frankly, I don't think ranked choice has any place here. It's like someone
asked for a tire for their car and you offer them a propeller instead.

I was thinking of assigning a 2-character ID for each candidate -- base 36
(10 digits plus 26 letters) would give you 1,296 possible IDs. So, 96
selections would need 192 characters. Our ballot ID is taking 36
characters, so that's 228 characters. I've read that PDF417 is supposed to
handle 1000 characters or more, but that's pushing it, I believe. I don't
know where my best sources are at the moment, but I seem to recall that
FedEx considers 350 characters to be the practical limit for PDF417 (this
may be where I read that http://www.idautomation.com/pdf417faq.html ).

Alan D.

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Received on Wed Dec 31 23:17:04 2008

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